7t^2-43t+66=0

Solution for 7t^2-43t+66=0 equation:

7t^2-43t+66=0

a = 7; b = -43; c = +66;
Δ = b2-4ac
Δ = -432-4·7·66
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-1}{2*7}=\frac{42}{14}
=3
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+1}{2*7}=\frac{44}{14}
=3+1/7
$